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MATHEMATICS
K. A. RODOSSKII
ON A NEW APPLICATION OF I. M. VINOGRADOV’S ESTIMATES TO THE THEORY OF THE RIEMANN ZETA-FUNCTION
(Presented by Academician I. M. Vinogradov on 3 VI 1960)
Let \(N(\Delta,T)\) be the number of zeros of the function \(\zeta(s)\), \(s=\sigma+it\), lying in the rectangle \(\Delta\leqslant \sigma\leqslant 1,\ 0\leqslant t\leqslant T\). If \(\Delta\) and \(T\) are regarded as varying independently of one another, \(T>1\) and \(\Delta\in(1/2,1)\), then all our information on the behavior of \(N(\Delta,T)\) is expressed by inequalities of the form
\[ N(\Delta,T)<c_1\ln^{c_2}T\cdot T^{\varkappa(\Delta)(1-\Delta)}. \tag{1} \]
Here and below \(c_\nu\) denote absolute positive constants, \(\varkappa(\Delta)\geqslant 0\). Various methods for obtaining inequalities of type (1) give different estimates for the function \(\varkappa(\Delta)\). It is known, for example, that
\[ \varkappa(\Delta)\leqslant \min\left\{\frac{3}{2-\Delta},\ 2(1+2c)\right\}, \tag{2} \]
where
\[ c=\lim_{t\to\infty}\frac{\ln|\zeta(1/2+it)|}{\ln t} \]
(see \((^{1})\), Ch. IX, §§ 18—19). The best known value for \(c\) is \(15/92\) (see \((^{1})\), Ch. V, § 16). Inequality (2) is used in the solution of certain problems connected with prime numbers (see \((^{2,3})\)). If it were known that \(\varkappa(\Delta)\leqslant 2\), then in the solution of certain number-theoretic problems one would obtain, qualitatively, the same results as follow from the assumption of the truth of the Riemann hypothesis on the zeros of the zeta-function. However, from (2) one obtains only that \(\lim \varkappa(\Delta)=2+0\) as \(\Delta\to 1/2\). In the author’s paper \((^{4})\) it was pointed out that the estimate of \(\varkappa(\Delta)\) as \(\Delta\to 1\) can be considerably improved by means of the method of trigonometric sums. Later P. Turán \((^{5})\) obtained the estimate
\[ \varkappa(\Delta)\leqslant 2+600(1-\Delta)^{0.01} \tag{3} \]
for \(\Delta\) sufficiently close to 1 (in a note he gives, without proof, the better estimate \(\varkappa(\Delta)\leqslant 2+(1-\Delta)^{0.14}\)).
In this note it is shown that a proper application of new results of I. M. Vinogradov (see \((^{6})\)) leads to the estimate
\[ \varkappa(\Delta)\leqslant 2+c_3(1-\Delta)^{1/3}. \tag{4} \]
The proof of inequality (4) is based on the following lemmas. Below \(\rho=\beta+i\gamma\) denotes a zero of the zeta-function lying in the rectangle \(R\{\Delta\leqslant \sigma\leqslant 1,\ \tfrac12 T\leqslant t\leqslant T\}\).
Lemma 1.
\[
\left|\sum_{n<x} n^{-\rho}\right|\leqslant c_4 x^{1-\beta}T^{-1}\quad \text{for } x\geqslant T.
\]
Proof see \((^{1})\), Chapter IV, § 3.
Lemma 2. For \(k\geqslant 7\) and under the condition
\((k+1)^{-1}\ln T \leqslant \ln x \leqslant k^{-1}\ln T\), we have
\[
\left|\sum_{x<n\leqslant T} n^{-\rho}\right|
\leqslant c_{5}\ln T\cdot x^{1-c_{6}k^{-2}-\beta}.
\]
Proof. This is a simple consequence of I. M. Vinogradov’s estimates of trigonometric sums \((^{6})\) and of Korput’s estimates (see \((^{1})\), Ch. V, Th. 11).
Let
\[
f(s)=\sum_{y<n\leqslant z} a_n n^{-s},
\quad\text{where}\quad
a_n=\sum_{d\mid n,\ d>y}\mu(d),
\]
and \(\mu(d)\) is the Möbius function.
Lemma 3. If for every zero \(\rho\in R\) of the zeta-function the inequality \(|f(\rho)|\geqslant 1/2\) holds, then the number \(Q(\Delta,T)\) of zeros belonging to \(R\) does not exceed
\[
c_{7}\ln^{8}T\cdot\bigl(Ty^{1-2\Delta}+z^{2-2\Delta}\bigr).
\]
Proof follows trivially from Theorem 1 of paper \((^{7})\).
On the basis of the lemmas stated above, the proof of the theorem reduces to the following. Put \(y_1=zT^{-1}\), \(z>T>y>y_1\), and use the identity
\[
\begin{aligned}
1={}&
\sum_{n\leqslant y_1}\mu(n)n^{-\rho}\sum_{kn\leqslant z}k^{-\rho}
+\sum_{y_1<n\leqslant y}\mu(n)n^{-\rho}\sum_{k\leqslant T}k^{-\rho}
\\
&-\sum_{y_1<n\leqslant y}\mu(n)n^{-\rho}\sum_{zn^{-1}<k\leqslant T}k^{-\rho}
+\sum_{y<n\leqslant z}\mu(n)n^{-\rho}\sum_{kn\leqslant z}k^{-\rho}.
\end{aligned}
\tag{5}
\]
With the help of Lemma 1 we estimate
\[
\left|\sum_{n\leqslant y_1}\mu(n)n^{-\rho}\sum_{kn\leqslant z}k^{-\rho}\right|
+
\left|\sum_{y_1<n\leqslant y}\mu(n)n^{-\rho}\sum_{k\leqslant T}k^{-\rho}\right|
<\frac14
\tag{6}
\]
under the conditions \(z<T^2\), \(\Delta>3/4\), and \(T>T_0\). It is enough to consider only
\[
\Delta \leqslant 1-c_{9}\ln\ln T\cdot \ln^{-1}T.
\]
Define \(k\) from the inequalities
\[
\frac{c_6}{4}(k+1)^{-3}\leqslant 1-\Delta \leqslant \frac{c_6}{4}k^{-3}
\]
(this is possible for values of \(\Delta\) sufficiently close to 1), and put
\[
y=zT^{-\frac{1}{k+1}}.
\]
With the help of Lemma 2 we obtain
\[
\left|
\sum_{y_1<n\leqslant y}\mu(n)n^{-\rho}
\sum_{zn^{-1}<k\leqslant T} k^{-\rho}
\right|
\leqslant
c_7c_6^{-1}k^2\ln T\cdot z^{1-\Delta}T^{-c_6k^{-3}}
<\frac14
\tag{7}
\]
for sufficiently large \(T\). From identity (5) and inequalities (6) and (7) we obtain \(|f(\rho)|\geqslant 1/2\), and Lemma 3 can be applied. To estimate \(\chi(\Delta)\), it is enough to consider the expression
\[
Ty^{1-2\Delta}+z^{2-2\Delta}.
\]
Its minimal value is obtained from the condition
\[
Ty^{1-2\Delta}=z^{2-2\Delta}
\]
or
\[
Tz^{1-2\Delta}T^{\frac{2\Delta-1}{k+1}}=z^{2-2\Delta},
\]
whence it follows that
\[
z=T^{1+\frac{2\Delta-1}{k+1}},
\]
and the estimate
\[
\chi(\Delta)\leqslant
2\left(1+\frac{2\Delta-1}{k+1}\right)
\leqslant
2+2\left[\frac{c_6}{4}(1-\Delta)\right]^{1/3}.
\]
Putting \((2c_6)^{1/3}=c_3\), we obtain estimate (4).
Voronezh State University
Received
21 V 1960
REFERENCES
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