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Reports of the Academy of Sciences of the USSR
1961. Vol. 141, No. 3
MATHEMATICS
M. K. POTAPOV
ON THE FOURIER COEFFICIENTS OF PERIODIC FUNCTIONS BELONGING TO THE \(H\)-CLASSES OF S. M. NIKOLSKII
(Presented by Academician A. N. Kolmogorov on 23 VI 1961)
I. As usual \((^1)\), we shall say that a function \(f(x)\), periodic with period \(2\pi\), belongs to the class \(H_p^{(r)}\), where \(1 \le p \le \infty\), \(r=\bar r+\alpha\), \(0<\alpha\le 1\), \(\bar r\) is an integer, if \(f(x)\) has an \(\bar r\)-th derivative such that \(f^{(\bar r)}(x)\in L_p\) and
\[ \bigl\|f^{(\bar r)}(x+h)-2f^{(\bar r)}(x)+f^{(\bar r)}(x-h)\bigr\|_{L_p}\le |h|^\alpha, \]
where in this inequality, for \(0<\alpha<1\), the second difference may be replaced by the first. By \(E_n(f)_{L_p}\) we shall denote the best approximation, in the metric \(L_p\), of the periodic function \(f(x)\) by trigonometric polynomials of order \(n\).
It is well known \((^1)\):
Theorem A. In order that \(f(x)\in H_p^{(r)}\), it is necessary and sufficient that \(E_n(f)_{L_p}\le C/n^r\).
Since we are dealing with periodic functions, it would naturally be desirable to pose the question of the existence of conditions, simultaneously necessary and sufficient for \(f(x)\in H_p^{(r)}\), not in terms of best approximations, but in terms of the Fourier coefficients of the function \(f(x)\). For even and odd functions such conditions are known \((^{2,3})\), namely: if
\[ f(x)\sim \sum_{k=1}^{\infty} a_k\cos kx \]
or
\[ f(x)\sim \sum_{k=1}^{\infty} a_k\sin kx \]
and \(a_k\downarrow\), then the conditions
\[ |a_k|\le C/k^{r+1-1/p} \]
are necessary and sufficient in order that \(f(x)\in H_p^{(r)}\), \(1<p\le\infty\). From Theorems 3, 4, and 5 given below it follows, in particular, that in the general case no such conditions exist.
II. Theorem 1. In order that a periodic function
\[ f(x)\sim \sum_{k=-\infty}^{\infty} C_k e^{ikx} \]
belong to the class \(H_p^{(r)}\), \(1\le p\le\infty\), it is sufficient that its Fourier coefficients satisfy the following conditions:
\[ \text{for } 2\le p\le\infty \qquad \left(\sum_{|k|=n+1}^{\infty}|C_k|^{p'}\right)^{1/p'}\le \frac{C}{n^r}, \qquad \frac{1}{p}+\frac{1}{p'}=1; \tag{1} \]
\[ \text{for } 1\le p\le 2 \qquad \left(\sum_{|k|=n+1}^{\infty}|C_k|^2\right)^{1/2}\le \frac{C}{n^r}. \tag{2} \]
Proof. Obviously, for any \(p\), \(1\le p\le\infty\),
\[ E_n(f)\le \|f(x)-s_n(x)\|_{L_p}\, *. \]
Let \(2\le p\le\infty\); then, on the basis of the theo—
\(*\) Here and below, \(s_n(x)\) denotes the partial sum of the Fourier series for \(f(x)\).
by the Hausdorff—Young theorem ((4), p. 131), it follows from this inequality that
\[ E_n(f)_{L_p}\leqslant \left(\sum_{|k|=n+1}^{\infty}|C_k|^{p'}\right)^{1/p'} . \tag{3} \]
Let \(1\leqslant p\leqslant 2\); then, obviously,
\[ E_n(f)_{L_p}\leqslant C E_n(f)_{L_2} = C\left(\sum_{|k|=n+1}^{\infty}|C_k|^2\right)^{1/2}; \tag{4} \]
if now \(f(x)\) satisfies the conditions of Theorem 1, then from inequalities (3) or (4) and Theorem A there follows the validity of Theorem 1. We note that Theorem 1 cannot be strengthened (see below the example to Theorem 3).
Theorem 2. If a periodic function
\[ f(x)\sim \sum_{k=-\infty}^{\infty} C_k e^{ikx} \]
belongs to the class \(H_p^{(r)}\), \(1<p\leqslant \infty\), then its Fourier coefficients must satisfy the following conditions:
\[ \text{for } 2\leqslant p\leqslant \infty \qquad \left(\sum_{|k|=n+1}^{\infty}|C_k|^2\right)^{1/2}\leqslant \frac{C}{n^r}; \tag{5} \]
\[ \text{for } 1<p\leqslant 2 \qquad \left(\sum_{|k|=n+1}^{\infty}|C_k|^{p'}\right)^{1/p'}\leqslant \frac{C}{n^r}, \qquad \frac1p+\frac1{p'}=1. \tag{6} \]
Proof. It is easy to show (see, for example, (5), p. 77) that for \(1<p<\infty\)
\[ \|f(x)-s_n(x)\|_{L_p}\leqslant C E_n(f)_{L_p}. \]
Therefore, if \(f(x)\in H_p^{(r)}\), then for \(1<p\leqslant 2\)
\[ \|f(x)-s_n(x)\|_{L_p}\leqslant C/n^r, \]
whence, on the basis of the Hausdorff—Young theorem, there follows the validity of inequality (6). Let now \(2\leqslant p\leqslant \infty\). Then, obviously,
\[ E_n(f)_{L_2}\leqslant C E_n(f)_{L_p}, \]
whence, on the basis of Parseval’s equality and the conditions of the theorem, there follows the validity of inequality (5). The theorem is proved. We note that Theorem 2 cannot be sharpened (see below the examples to Theorems 4 and 5).
As a consequence of Theorem 1, the following is proved quite simply.
Theorem 3. In order that a periodic function
\[ f(x)\sim \sum_{k=-\infty}^{\infty} C_k e^{ikx} \]
belong to the class \(H_p^{(r)}\), \(1\leqslant p\leqslant \infty\), it is sufficient that its Fourier coefficients satisfy the following conditions:
\[ \text{for } 1\leqslant p\leqslant 2 \qquad |C_k|\leqslant C/(|k|+1)^{r+1/2}; \tag{7} \]
\[ \text{for } 2\leqslant p\leqslant \infty \qquad |C_k|\leqslant C/(|k|+1)^{r+1-1/p}. \tag{8} \]
Let us give examples showing that Theorem 3 cannot be strengthened.
Case \(2\leqslant p\leqslant \infty\). Consider
\[ f(x)\sim \sum_{n=1}^{\infty}\frac{\cos(nx-r\pi/2)}{n^{r+1-1/p}} . \]
The function \(f(x)\) satisfies the conditions of Theorem 3; therefore it belongs to the class \(H_p^{(r)}\). We shall show that \(f(x)\) cannot have a derivative in the sense of Weyl of order \(r\) belonging to \(L_p\), i.e. \(f(x)\notin W_p^{(r)}\). Hence it will follow that \(f(x)\) cannot belong to the better class \(H_p^{(\rho)}\), where \(\rho>r\), since \(H_p^{(\rho)}\subset W_p^{(r)}\subset H_p^{(r)}\).
Suppose the contrary—that \(f(x)\) has a derivative of order \(r\) belonging to \(L_p\), i.e. \(f^{(r)}(x)\in L_p\); then we would have
\[ f^{(r)}(x)\sim \]
\[
\sim \sum_{k=1}^{\infty} a_k \cos kx,\quad \text{where}\quad a_k=\frac{1}{k^{1-1/p}}.
\]
By assumption, \(f^{(r)}(x)\) must belong to \(L_p\). But in order that, for \(1<p<\infty\), the function
\[
\varphi(x)\sim \sum_{k=1}^{\infty} a_k\cos kx,\quad \text{where } a_1\geq a_2\geq\cdots\to 0,
\]
belong to \(L_p\), it is necessary and sufficient ((4), p. 212) that the expression
\[
\sum_{k=1}^{\infty} a_k^p k^{p-2}
\]
be finite; in our case it is infinite. Hence, for \(2\leq p<\infty\) our assumption is false and the theorem cannot be strengthened.
For \(p=\infty\), the function \(f^{(r)}(x)=-\log 2\sin \tfrac12 x\), and this function does not belong to \(L_\infty\); hence, for \(p=\infty\) too, our assumption is false and the theorem cannot be strengthened.
Case \(1\leq p\leq 2\). Consider
\[
f(x)\sim \sum_{k=1}^{\infty}\frac{\varepsilon_k}{k^{r+1/2}}\cos\left(nx-r\frac{\pi}{2}\right),
\]
where \(\varepsilon_k=\pm 1\) and the plus and minus signs are chosen so that the series
\[
\sum_{k=1}^{\infty}\pm \frac{\cos kx}{k^{1/2}}
\]
is not a Fourier series. The function \(f(x)\) satisfies the conditions of Theorem 3, and therefore it belongs to the class \(H_p^{(r)}\). To show that Theorem 3 cannot be strengthened, it suffices, as above, to show that the function \(f(x)\) cannot have a derivative of order \(r\) belonging to \(L_p\). Assuming the contrary, we would have \(f^{(r)}(x)\in L_p\) and
\[
f^{(r)}(x)\sim \sum_{k=1}^{\infty}\pm \frac{\cos kx}{k^{1/2}} .
\tag{9}
\]
Since the series (9) is not a Fourier series, our assumption about the existence of \(f^{(r)}(x)\in L_p\) is false, and this means that the theorem cannot be strengthened.
Theorem 4. If the periodic function
\[
f(x)\sim \sum_{k=-\infty}^{\infty} C_k e^{ikx}
\]
belongs to the class \(H_p^{(r)}\), then its Fourier coefficients necessarily satisfy the conditions
\[
|C_k|\leq C/(|k|+1)^r,\qquad |k|=0,1,2,\ldots .
\tag{10}
\]
Theorem 4 is known (see, for example, (4), p. 22); it is included here for completeness of exposition. Theorem 4 cannot be sharpened. Indeed, the function
\[
f(x)=\sum_{k=1}^{\infty}\frac{1}{2^{kr}}\cos\left(2^kx+r\frac{\pi}{2}\right)
\]
satisfies the conditions of Theorem 4, i.e. \(|C_k|\leq C/(|k|+1)^r\) and \(f(x)\in H_p^{(r)}\), but \(f(x)\notin W_p^{(r)}\).
Remark. Assuming that \(|C_k|\downarrow\), Theorem 4 can be sharpened (see Theorem 5). However, as the examples to Theorem 3 show, the assumption that \(|C_k|\downarrow\) does not allow Theorem 3 to be sharpened.
Theorem 5. If the periodic function
\[
f(x)\sim \sum_{k=-\infty}^{\infty} C_k e^{ikx}
\]
belongs to the class \(H_p^{(r)}\), \(1\leq p\leq \infty\), and
\[
2|C_0|\geq |C_1|+|C_{-1}|\geq |C_2|+|C_{-2}|\geq \cdots,
\]
i.e. \(|C_k|\downarrow\), then its Fourier coefficients necessarily satisfy the following conditions:
\[
\text{for } 2\leq p<\infty \qquad |C_k|\leq C/(|k|+1)^{r+1/2};
\tag{11}
\]
\[
\text{for } 1\leq p\leq 2 \qquad |C_k|\leq C/(|k|+1)^{r+1-1/p}.
\tag{12}
\]
Proof. Let \(|C_k|\downarrow\), i.e.
\[
2|C_0|\ge |C_1|+|C_{-1}|\ge |C_2|+|C_{-2}|\ge\cdots;
\]
then
\[
\sum_{k=[n/2]+1}^{n}\frac{|C_k|}{|k|}
\ge (|C_n|+|C_{-n}|)\left(\frac{1}{[n/2]+1}+\cdots+\frac{1}{n}\right)
\ge \frac{|C_n|+|C_{-n}|}{2},
\]
whence
\[
|C_n|+|C_{-n}|\le
\]
\[
\le 2\sum_{k=[n/2]+1}^{\infty}\frac{|C_k|}{|k|}
\le
2\left(\sum_{|k|=[n/2]+1}^{\infty}\frac{1}{|k|^p}\right)^{1/p}
\left(\sum_{|k|=[n/2]+1}^{\infty}|C_k|^{p'}\right)^{1/p'},
\tag{13}
\]
\[
\frac{1}{p}+\frac{1}{p'}=1.
\]
Let the function \(f(x)\) satisfy the conditions of Theorem 5. Then for \(1<p\le 2\) the validity of Theorem 5 follows from inequality (13) and Theorem 2, while for \(2\le p\le\infty\) the validity of Theorem 5 follows from inequality (13), if in it one puts \(p=p'=2\), and also from Theorem 2. For \(p=1\), Theorem 5 is a particular case of Theorem 4.
We give examples showing that Theorem 5 cannot be sharpened.
Case \(2\le p\le\infty\). Consider
\[
f(x)=\sum_{n=2}^{\infty}\frac{e^{i n\ln n}}{n^{r+1/2}}e^{inx}.
\]
This function has Fourier coefficients satisfying inequality (11) and such that \(|C_k|\downarrow\). We shall show that \(f(x)\in H_p^{(r)}\) for every \(p\).
Indeed, for \(p=\infty\) the function \(f(x)\in H_\infty^{(r)}\), for if \(r=\bar r+\alpha\), where \(0<\alpha\le 1\), and \(\bar r\) is an integer, then
\[
f^{(\bar r)}(x)=\sum_{n=2}^{\infty}\frac{e^{i n\ln n}}{n^{\alpha+1/2}}e^{inx}\in H_\infty^{(\alpha)}
\]
(see \((^4)\), p. 140)*, i.e. \(f(x)\in H_p^{(r)}\) for every \(p\). We further show that \(f(x)\notin W_p^{(r)}\). Assuming the contrary, we obtain that \(f^{(r)}(x)\in L_p\) and
\[
f^{(r)}(x)\sim \sum_{n=2}^{\infty}\frac{e^{i n\ln n}}{n^{1/2}}e^{inx}.
\]
However, this is not so, since for \(p=\infty\), \(f^{(r)}(x)\notin L_\infty\) (see \((^4)\), p. 122), and for \(p=2\), \(\|f^{(r)}(x)\|_{L_2}=\infty\), i.e. \(f^{(r)}(x)\notin L_2\). This means that \(f^{(r)}(x)\notin L_p\) for all \(p\) in the interval \(2\le p\le\infty\), i.e. Theorem 5 in this case is not sharpenable.
Case \(1<p\le 2\). Consider
\[
f(x)\sim \sum_{k=1}^{\infty}\frac{\cos(kx-r\pi/2)}{k^{r+1-1/p}}.
\]
This function has Fourier coefficients satisfying inequality (12) and such that \(|C_k|\downarrow\). Moreover, it belongs to the class \(H_p^{(r)}\), \(1<p\le 2\) (see \((^2)\), p. 436), and does not belong to a better class \(f(x)\notin W_p^{(r)}\) (see the example to Theorem 3), i.e. Theorem 5 is not sharpened in this case either.
The case \(p=1\) has already been considered earlier (see the example to Theorem 4).
Moscow State University
named after M. V. Lomonosov
Received
23 VI 1961
References
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- A. A. Konjushkov, Izv. AN SSSR, ser. matem., 21, No. 3, 423 (1957).
- G. G. Lorentz, Math. Zs., 51, No. 2 (1948).
- A. Zygmund, Trigonometric Series, Moscow–Leningrad, 1933.
- M. K. Potapov, Uch. zap. Ivanovsk. gos. ped. inst., 18 (1958).
* In \((^4)\) it is proved that \(f^{(\bar r)}(x)\in H_\infty^\alpha\) only for \(0<\alpha<1\); however, for \(\alpha=1\) the proof is analogous.