D. M. CHIBISOV
Unknown
Submitted 1961-01-01 | RussiaRxiv: ru-196101.74629 | Translated from Russian

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D. M. CHIBISOV

ON THE ASYMPTOTIC POWER AND EFFICIENCY OF THE CRITERION \(\omega_n^2\)

(Presented by Academician A. N. Kolmogorov, 20 XII 1960)

§ 1.

Let \(x_1, x_2, \ldots, x_n\) be a sample of \(n\) independent observations of a random variable with distribution function \(F(x)\). We shall denote the empirical distribution function of such a sample by \(F^{(n)}(x)\). The criterion \(\omega_n^2\) is a criterion for testing the simple hypothesis \(F(x)=F_0(x)\), based on the statistic

\[ \omega_n^2(F)=n\int_{-\infty}^{\infty}\bigl[F^{(n)}(x)-F_0(x)\bigr]^2\psi(F_0(x))\,dF_0(x), \tag{1} \]

where \(\psi(u)\ge 0\) \((0\le u\le 1)\) is a certain weight function. We introduce the argument \(F\) to denote the true distribution of the sample. Under the assumption \(F(x)=F_0(x)\), the limiting distribution of the quantity \(\omega_n^2\) as \(n\to\infty\) was studied by N. V. Smirnov \((^1)\) and by Anderson and Darling \((^2)\).

Denote
\[ W^{(n)}(x;F)=\mathbf P\{\omega_n^2(F)<x\} \]
and
\[ P_\alpha^{(n)}(F)=1-W^{(n)}(x_\alpha;F), \]
where \(x_\alpha\) is the root of the equation \(W(x;F_0)=1-\alpha\). At significance level \(\alpha\), \(P_\alpha^{(n)}(F)\) is the power function of the criterion (the probability of rejecting the hypothesis if the alternative \(F(x)\) is true).

Denote

\[ \rho_F^2=\int_{-\infty}^{\infty}\bigl[F(x)-F_0(x)\bigr]^2\psi(F_0(x))\,dF_0(x). \tag{2} \]

Let the function \(\delta(u)\), \(0\le u\le 1\), be such that \(\delta(0)=\delta(1)=0\) and

\[ \int_0^1 \delta^2(u)\psi(u)\,du=1. \tag{3} \]

We shall call the class of functions of the form
\[ F_a(x)=F_0(x)+\frac{a}{\sqrt n}\,\delta(F_0(x)) \]
the class \([\delta(u)]\). By (3), \(a^2=n\rho_{F_a}^2\). For functions \(F_a(x)\in[\delta(u)]\), we introduce the notation \(\omega_n^2(a)\), \(W^{(n)}(x,a)\), and \(P_\alpha^{(n)}(a)\) instead of \(\omega_n^2(F_a)\), \(W^{(n)}(x;F_a)\), and \(P_\alpha^{(n)}(F_a)\).

Denote by \(\lambda_j\) and \(f_j(u)\) \((j=1,2,\ldots)\) the eigenvalues and eigenfunctions of the integral equation

\[ f(u)=\lambda\int_0^1 K(u,v)f(v)\,dv, \]

where
\[ K(u,v)=[\min(u,v)-uv]\sqrt{\psi(u)}\sqrt{\psi(v)},\qquad 0\le u,v\le 1. \]
The kernel \(K(u,v)\) is positive definite, whence \(\lambda_j>0\) \((j=1,2,\ldots)\); we shall assume that \(\lambda_k\ge \lambda_j\) for \(k>j\). In addition, the system of eigenfunctions \(\{f_j(u)\}\) may be chosen orthonormal:

\[ \int_0^1 f_j(u) f_k(u)\,du=\delta_{jk}. \]
By \(D(\lambda)\) we shall denote the Fredholm determinant of the integral equation.

§ 2. Suppose:

I. The functions \(F_0(x)\) and \(\delta(u)\) are continuous.

II. The function \(\psi(u)\) is continuous in any interval \(0<u_1\le u\le u_2<1\), and the integral
\[ \int_0^1 u(1-u)\psi(u)\,du=\int_0^1 K(u,u)\,du \]
exists.

III. The integral
\[ \int_0^1 \delta(u)\psi(u)\,du \]
exists.

IV. For the expansion
\[ \delta(u)\sqrt{\psi(u)}=\sum_{k=1}^{\infty}\delta_k f_k(u), \]
where
\[ \delta_k=\int_0^1 f_k(u)\delta(u)\sqrt{\psi(u)}\,du, \]
the closure condition is satisfied.

Theorem 1. If conditions I–III are satisfied, \(W^{(n)}(x,a)\), for each \(a\), converges weakly as \(n\to\infty\) to \(W(x,a)=\mathbf P\{\omega^2(a)<x\}\), where
\[ \omega^2(a)=\int_0^1 [y(u)+a\delta(u)]^2\psi(u)\,du, \tag{4} \]
\(y(u)\), \(0\le u\le 1\), is a Gaussian random process with \(\mathbf M y(u)=0\), \(\mathbf M y(u)y(v)=\min(u,v)-uv\).

Theorem 2. Under conditions I–IV, \(W(x,a)\) has the characteristic function
\[ \varphi(t,a)=\frac{1}{\sqrt{D(2it)}}\exp\left\{a^2\sum_{k=1}^{\infty}\frac{it\lambda_k\delta_k^2}{\lambda_k-2it}\right\}. \tag{5} \]

Let us note the expansion from which (5) is obtained:
\[ \omega^2(a)=\sum_{k=1}^{\infty}\left(\frac{X_k}{\sqrt{\lambda_k}}+a\delta_k\right)^2, \tag{6} \]
where \(\{X_k\}\) are independent normally \((0,1)\) distributed quantities.

Theorem 3. As \(a\to\infty\),
\[ W(x,a)-\Phi\left(\frac{x-a^2}{2a\sigma}\right)\to 0 \tag{7} \]
uniformly in \(x\). Here
\[ \Phi(x)=\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{x} e^{-t^2/2}\,dt \]
and
\[ \sigma^2=\int_0^1\int_0^1 K(u,v)\delta(u)\delta(v)\sqrt{\psi(u)}\sqrt{\psi(v)}\,du\,dv. \tag{8} \]

Proof. The quantity
\[ \xi=\int_0^1 y(u)\delta(u)\psi(u)\,du \]
is normally distributed with parameters \((0,\sigma)\). From (4) and (3) we obtain
\[ W(x,a)=\mathbf P\{\omega^2(a)<x\} =\mathbf P\{\omega^2(0)+2a\xi+a^2<x\} \]
\[ =\mathbf P\left\{\frac{\omega^2(0)}{2a}+\xi<\frac{x-a^2}{2a}\right\}, \tag{9} \]
whence (7) follows.

Chapman [3] was the first to point out the validity of (7), proceeding from somewhat different considerations.

  1. It can be shown that, for each \(x\), \(W^{(n)}(x,a)\to W(x,a)\) uniformly in \(a\).

  2. From (5) it follows that \(W(x,a)=W(x,-a)\); we shall therefore assume \(a\geqslant 0\).

  3. From (6) it follows that, for each \(x>0\), the function \(W(x,a)\) decreases monotonically (in \(a\)), since the distribution function of each of the terms has this property. Hence it follows that \(P_\alpha(a)\) increases monotonically; in particular, \(P_\alpha(a)>P_\alpha(0)=\alpha\), if \(a>0\). Thus, \(\omega^2\) is an asymptotically unbiased test.

  4. From (9) it follows that, for all \(x\) and \(a\),

\[ W(x,a)<\Phi\left(\frac{x-a^2}{2a\sigma}\right), \]

which gives a lower bound for the power function:

\[ P_\alpha(a)>1-\Phi\left(\frac{x_\alpha-a^2}{2a\sigma}\right). \]

  1. From (8) and (3) we obtain the estimate

\[ \sigma^2=\sum_{k=1}^{\infty}\frac{\delta_k^2}{\lambda_k}<\frac{1}{\lambda_1}. \]

Now from (10) it follows that, for the family of alternatives \(\{F(x)\}\) with

\[ \rho_F\geqslant \frac{\sqrt{x_\alpha}}{\sqrt{n}}, \]

\[ P_\alpha(F)\geqslant 1-\Phi\left(\frac{x_\alpha-n\rho_F^2}{2\rho_F\sqrt{n}}\sqrt{\lambda_1}\right) \]

uniformly for all distribution functions of the family. In particular, if a sequence of alternatives \(\{F_n(x)\}\) is such that \(\rho_{F_n}\sqrt{n}\to\infty\), then \(P_\alpha(F_n)\to 1\).

  1. For \(a\leqslant x\)

\[ W(x,a)=\mathrm{P}\{\omega^2(0)+2a\xi<x-a^2\}> \mathrm{P}\left\{\omega^2(0)<x-a^2-2a\frac{1}{\sqrt{a}}\right\}- \]

\[ -\mathrm{P}\left\{\xi>\frac{1}{\sqrt{a}}\right\}\geqslant W(x-a^2-2\sqrt{a},0)- \left[1-\Phi\left(\left(\frac{1}{\sqrt{a}}-\sqrt{x}\right)\sqrt{\lambda_1}\right)\right], \]

or, for \(a\leqslant x_\alpha\),

\[ P_\alpha(a)\leqslant 1-W(x_\alpha-a^2-2\sqrt{a},0)- \left[1-\Phi\left(\left(\frac{1}{\sqrt{a}}-\sqrt{x_\alpha}\right)\sqrt{\lambda_1}\right)\right]. \]

Hence, if a sequence \(\{F_n(x)\}\) is such that \(\rho_{F_n}=o(1/\sqrt{n})\), then \(P_\alpha(F_n)\to\alpha\).

  1. From (5) the semi-invariants of \(W(x,a)\) are easily found:

\[ k_n(a)=2^{\,n-1}(n-1)!\left(\sum_{j=1}^{\infty}\frac{1}{\lambda_j^n} +a^2 n\sum_{j=1}^{\infty}\frac{\delta_j^2}{\lambda_j^{\,n-1}}\right) =2^{\,n-1}(n-1)!\left(\int_0^1 K_n(u,u)\,du+\right. \]

\[ \left. +a^2 n\int_0^1\int_0^1 K_{n-1}(u,v)\delta(u)\delta(v)\sqrt{\psi(u)}\sqrt{\psi(v)}\,du\,dv\right), \]

where \(K_n(u,v)\) is the \(n\)-th iteration of the kernel \(K(u,v)\).

  1. Put

\[ \nu_n(x_\alpha)=\int_{+0}^{\infty} a^n\,dP_\alpha(a). \]

Using (5), one can find the Laplace transform of \(\nu_n(x)\):

\[ \widetilde{\nu}_n(p)=\int_0^\infty e^{-px}\nu_n(x)\,dx =\Gamma(n/2+1)\left|p\sqrt{D(-2p)}\right| \left(\sum_{k=1}^{\infty}\frac{\lambda_k\delta_k^2 p}{\lambda_k+2p}\right)^{n/2}. \]

§ 3. To compute the asymptotic efficiency of the criterion in the general case, we shall find, for the family of alternatives \([\delta(u)]\), the asymptotically most powerful criterion and its power function \(P_\alpha^*(a)\). Then, if \(P_\alpha^*(a^*)=P_\alpha(a)=1-\beta\), where \(\beta\) is the prescribed error of the second kind, the asymptotic efficiency of the criterion is equal to \(e=a^{*2}/a^2\).

Under condition I, without loss of generality one may take \(F_0(x)=x\), \(0\leq x\leq 1\). Then \(F_a(x)=x+\dfrac{a}{\sqrt n}\delta(x)\).

Theorem 4. Suppose that \(\delta(u)\) is differentiable and that the integral

\[ s^2=\int_0^1[\delta'(u)]^2\,du \]

exists. Then, if \(F(x)=F_a(x)\), the quantity

\[ T^{(n)}=\frac{1}{\sqrt n}\sum_{i=1}^n \delta'(x_i) \]

is asymptotically normally distributed \((as^2,\ s)\), and the criterion based on the statistic \(T^{(n)}\) is the asymptotically most powerful criterion for testing the hypothesis \(F(x)=x\) against the alternative \(F(x)=F_a(x)\).

Proof. Since \(T^{(n)}\) is a sum of independent identically distributed terms, the first assertion follows directly from the central limit theorem. The second assertion follows from the fact that the criterion \(T^{(n)}\) is asymptotically equivalent to the criterion based on the likelihood ratio

\[ \sum_{i=1}^n \ln\left[1+\frac{a}{\sqrt n}\delta'(x_i)\right]. \]

Denote by \(z_\alpha\) the root of the equation \(1-\Phi(z)=\alpha\). The power function of the criterion \(T^{(n)}\) is asymptotically equal to \(\Phi(|a|s-z_\alpha)\). Using (10), we obtain

\[ e\geq \frac{z_\alpha+z_\beta} {s\left(\sigma z_\beta+\sqrt{\sigma^2 z_\beta^2+\chi_\alpha}\right)}. \]

For example, for the criterion with \(\psi\equiv 1\) under the hypothesis \(\Phi(x)\) and the alternatives \(\Phi(x-\mu)\) and \(\Phi\left(\dfrac{x}{1+\vartheta}\right)\), the efficiencies (\(e_\mu\) and \(e_\vartheta\), respectively) will be: for \(\alpha=\beta=0.05\), \(e_\mu\geq 0.53,\ e_\vartheta\geq 0.18\); for \(\alpha=\beta=0.01\), \(e_\mu\geq 0.56,\ e_\vartheta\geq 0.20\); for \(\alpha=\beta=0.001\), \(e_\mu\geq 0.58,\ e_\vartheta\geq 0.21\).

Steklov Mathematical Institute
Academy of Sciences of the USSR

Received
17 XII 1960

REFERENCES

  1. N. V. Smirnoff, C. R., 202, 449 (1936); N. V. Smirnov, Matem. sborn., 2 (44), no. 5, 973 (1937); UMN, 4, 4 (32), 196 (1949).
  2. T. W. Anderson, D. A. Darling, Ann. Math. Stat., 23, 2, 193 (1952).
  3. D. G. Chapman, Ann. Math. Stat., 29, 3, 655 (1958).

Submission history

D. M. CHIBISOV