Abstract
Full Text
MATHEMATICS
V. V. PROIZVOLOV
ON CONDENSATIONS ONTO EUCLIDEAN SPACES
(Presented by Academician P. S. Aleksandrov, March 12, 1963)
The main theorem of the present note is as follows:
Theorem 1. Let a condensation \(f:X\to E^n\) be given, where \(X\) is a connected, locally bicompact paracompact space, and \(E^n\) is Euclidean space. Then \(f\) is a homeomorphism.
For \(n=1\) this theorem has a strengthening:
Theorem 2. Let a condensation \(f:X\to L\) be given, where \(X\) is a connected and peripherally bicompact** space, and \(L\) is a line. Then \(f\) is a homeomorphism.
Proof of Theorem 2. In order that a condensation be a homeomorphism, it is necessary and sufficient that it be closed. Suppose that \(f\) is not closed. Then it is not hard to see that there will be a countable closed subset \(A\subset X\) such that \(fA\subset L\) is not closed. Let \(\xi=f^{-1}a\), where \(a\in [fA]\setminus fA\). The space \(X\) is Hausdorff, since it is condensed onto the Hausdorff space \(L\), and, being peripherally bicompact, it is completely regular \((^1)\). Therefore there exists at the point \(\xi\) a neighborhood \(O\xi\) with bicompact boundary \(F\) and such that \([O\xi]\cap A=\Lambda\), or, what is the same thing: \(f[O\xi]\cap fA=\Lambda\). There is an \(\varepsilon>0\) such that \(O_\varepsilon a\cap fF=\Lambda\).
The line \(L\) is representable as the sum of two rays: \(L=L^+\cup L^-\), \(L^+\cap L^-=a\). Essentially, two cases are logically possible:
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\(a\in [(L^-\setminus a)\cap f[O\xi]]\), \(a\in [(L^+\setminus a)\cap f[O\xi]]\), and, in addition, for example, \(a\in [L^-\cap fA]\). In this case we proceed as follows. Choose a point \(b\) from \(L^-\) such that \(b\in fO\xi\) and \(|a-b|<\varepsilon\), where \(\varepsilon\) is the distance from the point \(a\) to \(fF\). Denote the segment \([a,b]\) by \(I\). The set \(f^{-1}Q\), where \(Q=I\setminus f[O\xi]\), is open-and-closed in \(X\). The set \(f^{-1}Q\) is open, since \(f^{-1}Q=f^{-1}(a,b)\setminus [O\xi]\), and it is closed, for \(f^{-1}Q=f^{-1}I\setminus O\xi\). But this contradicts the connectedness of \(X\).
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\(a\in [(L^-\setminus a)\cap f[O\xi]]\), \(a\notin [(L^+\setminus a)\cap f[O\xi]]\). In this case \(P=f^{-1}(L^+\setminus a)\) is open-and-closed in \(X\). It is obvious that \(P\) is open and that \([P]\setminus P\) either consists of the single point \(f^{-1}a\), or is empty. But at \(f^{-1}a\), by virtue of the conditions of this case, there is a neighborhood containing no points of the set \(P\). Thus, the theorem is proved.
The following theorem also holds; I give it without proof.
Theorem 3. Let a condensation \(f:X\to L\) be given, where \(X\) is a connected and locally connected space, and \(L\) is a line. Then \(f\) is a homeomorphism.
Proof of Theorem 1. We shall call a point \(\xi\in E^n\) bad if the image of at least one neighborhood of the point \(f^{-1}\xi\) contains no neighborhood of the point \(\xi\). It is not hard to verify that the set of all bad points \(W\) is closed in \(E^n\). We shall show that \(W\) is nowhere dense in \(E^n\). Suppose the contrary: an open ball \(Q\) consists entirely of bad points, \(Q\subset W\). Let \(\xi\in Q\), \(x=f^{-1}\xi\), and let a neighborhood \(Ox\) have bicompact closure \([Ox]=B\).
* A condensation is a one-to-one continuous mapping.
** A space is peripherally bicompact if it has a base whose elements have bicompact boundaries.
If some point \(\eta \in fB\) were interior, then it could not be bad; hence \(fB\) is nowhere dense in \(Q\). Since \(X\) is finally compact, it follows from what has been proved that \(Q\) can be represented as the sum of a countable number of closed nowhere dense sets, which contradicts the theorem. Thus \(W\) is closed and nowhere dense.
We shall call a spherical neighborhood \(O\xi\) of a point \(\xi \in W\) special if \(O\xi = O_1 \cup O_2\), where \(f^{-1}O_1 = V\) is open-and-closed in \(f^{-1}O\xi\), and \(V\) is a neighborhood of the point \(f^{-1}\xi\) whose closure is bicompact. Note that \(O_1 \cap |O_2| \subseteq W\). The neighborhood \(V\) of the point \(f^{-1}\xi\) will be called conjugate to \(O\xi\). Every point \(\xi \in W\) has special neighborhoods of arbitrarily small radius. Construct a neighborhood \(OW\) of the set \(W\): mark an arbitrary \(\xi_0 \in W\) with its special neighborhood \(O\xi_0\); let the point \(\eta \in O\xi_0\), \(\eta \notin W\), but \(f^{-1}\eta \in V_0\), where \(V_0\) is conjugate to \(O\xi_0\). The neighborhood \(OW\) is an arbitrary neighborhood of \(W\) that is the sum of special neighborhoods of points of \(W\), each of which, except \(O\xi_0\), does not contain \(\eta\).
Since \(X \setminus f^{-1}W\) is mapped homeomorphically by \(f\) onto \(E^n \setminus W\), the boundary of \(f^{-1}OW\) is mapped homeomorphically onto the boundary of \(OW\). Mark the \(U\)-component of the set \(OW\) containing \(\xi_0\). We note that \(f^{-1}U\) is disconnected, \(f^{-1}U = \Gamma_1 \cup \Gamma_2\), where \(\Gamma_1\) is the sum of the neighborhoods \(V_\alpha\) conjugate to the special neighborhoods forming \(U\), and \(\Gamma_2\) contains the point \(\eta\). If \(R = W \cap U\) does not split \(U\), then \(R\) does not split \(E^n\) either, and then \(f^{-1}R\) is open-and-closed in \(X\), for \(U \setminus R\) is connected, while \(f^{-1}U\) is disconnected. But this contradicts the connectedness of \(X\). Suppose now that \(R\) does split \(U\); then \(R\) splits \(E^n\), since \(U\) was a connected neighborhood of the closed set \(R\), and such a splitting can be carried out:
\[
E^n \setminus R = \Delta_1 \cup \Delta_2,
\]
where \(\Delta_1\) and \(\Delta_2\) are open in \(E^n \setminus R\), \(\Delta_1 \cap \Delta_2 = \Lambda\), and also \(f\Gamma_1 \setminus R \subseteq \Delta_1\), \(f\Gamma_2 \subseteq \Delta_2\). It is now not hard to see that \(f^{-1}\Delta_2\) is open-and-closed in \(X\). This contradicts the connectedness of \(X\), and therefore the set of bad points \(W\) is empty. The theorem is proved.
Corollary 1. Every condensation of \(E^n\) onto itself is a homeomorphism.
Corollary 2. Let a condensation be given \(f: X \to I^n\), where \(X\) is connected, locally bicompact, and paracompact, and \(I^n\) is the \(n\)-dimensional cube. Then \(f\) is a homeomorphism.
Corollary 3. Let a condensation be given \(f: X \to S_n\) \((n \ne 1)\), where \(X\) is connected, locally bicompact, and paracompact, and \(S_n\) is the \(n\)-dimensional sphere. Then \(f\) is a homeomorphism.
Corollary 1 follows immediately from Theorem 1, but Corollaries 2 and 3 require proofs, which I omit.
Received
8 III 1963
Note added in proof. Recently I obtained a result more general than Theorem 1:
Theorem. Let a condensation be given \(f: X \to Y\), where \(X\) is a connected, locally bicompact space with a countable base, and \(Y\) is a locally connected, locally bicompact, and unicoherent space with a countable base. Then \(f\) is a homeomorphism.
REFERENCES
- E. G. Sklyarenko, DAN, 120, No. 6, 1200 (1958).