A. N. BOGAEVSKII
Unknown
Submitted 1963-01-01 | RussiaRxiv: ru-196301.95140 | Translated from Russian

Full Text

A. N. BOGAEVSKII

HARMONIC FUNCTIONS ON \(GL(2)\)

(Presented by Academician I. G. Petrovskii, 24 VI 1963)

We consider the full complex linear group of second order \(G = GL(2)\) with elements

\[ g=\left\|\begin{matrix} g_1 & g_2\\ g_3 & g_4 \end{matrix}\right\|. \]

By the Laplace operator on it we shall mean the second-order differential operator, invariant under the operators of right and left translations,

\[ \mathcal L \det \bar g \left( \frac{\partial^2}{\partial g_1\,\partial g_4} - \frac{\partial^2}{\partial g_2\,\partial g_3} \right), \]

where

\[ \frac{\partial}{\partial g_k} = \frac{\partial}{\partial u_k} + i\frac{\partial}{\partial v_k}, \qquad g_k=u_k+iv_k. \]

More precisely, on \(G\) there are two Laplace operators, namely:

\[ \mathcal L_1=\operatorname{Re}\mathcal L,\qquad \mathcal L_2=\operatorname{Im}\mathcal L. \]

A twice differentiable function \(f(g)\) on \(G\) satisfying the two Laplace equations

\[ \mathcal L_1 f(g)=0,\qquad \mathcal L_2 f(g)=0, \]

is called harmonic.

Let \(G_0\) be the full complex unimodular linear group of second order with elements

\[ g_0=\left\|\begin{matrix} g_1^0 & g_2^0\\ g_3^0 & g_4^0 \end{matrix}\right\|, \qquad \det g_0=1, \]

and let \(A\) be the subgroup of \(G_0\) consisting of matrices of the form

\[ \hat a=\left\|\begin{matrix} 1 & a\\ 0 & 1 \end{matrix}\right\|. \]

The homogeneous space \(H=G_0/A\) can be interpreted as the space of linear elements of the complex plane and identified with the space of triangular unimodular matrices

\[ h= \left\|\begin{matrix} \xi^{-1} & 0\\ 0 & \xi \end{matrix}\right\| \left\|\begin{matrix} 1 & 0\\ z & 1 \end{matrix}\right\| = \left\|\begin{matrix} \xi^{-1} & 0\\ \xi z & \xi \end{matrix}\right\|^{*}, \]

in which the group \(G_0\) acts as follows:

\[ h= \left\|\begin{matrix} \xi^{-1} & 0\\ \xi z & \xi \end{matrix}\right\| \xrightarrow{\,g_0\,} h^{*}=h\circ g_0 = \left\|\begin{matrix} \xi^{-1}(zg_2^0+g_4^0)^{-1} & 0\\ \xi(zg_1^0+g_3^0) & \xi(zg_2^0+g_4^0) \end{matrix}\right\|. \]

We shall refer the matrices \(h\) to the parameters \(z,\xi\):

\[ h=(z,\xi), \qquad h\circ g_0= \left( \frac{zg_1^0+g_3^0}{zg_2^0+g_4^0}, \, \xi(zg_2^0+g_4^0) \right). \]

We extend the group of transformations \(G_0\) of the space \(H\) to the group \(G\), putting, for \(g\in G\),

\[ h\circ g= \left\|\begin{matrix} \xi^{-1}(zg_2+g_4)^{-1} & 0\\ \xi(zg_1+g_3) & \xi(zg_2+g_4) \end{matrix}\right\| \quad \text{or} \quad h\circ g= \left( \frac{zg_1+g_3}{zg_2+g_4}, \, \xi(zg_2+g_4) \right). \]

In what follows we consider functions \(\varphi(h_1,h_2)=\varphi(z_1,z_2;\xi_1,\xi_2)\) of two linear elements \(h_1=(z_1,\xi_1)\), \(h_2=(z_2,\xi_2)\), satisfying

\[ \text{* For more details on this, see }(^{1,\,2}). \]

condition

\[ \varphi(\hat{\delta}h_1,\hat{\delta}h_2)=|\delta|^{-4}\varphi(h_1,h_2), \qquad \text{where }\quad \hat{\delta}= \begin{pmatrix} \delta^{-1}&0\\ 0&\delta \end{pmatrix}, \]

or, more explicitly,

\[ \varphi(z_1,z_2;\delta\xi_1,\delta\xi_2) = |\delta|^{-4}\varphi(z_1,z_2;\xi_1,\xi_2). \tag{1} \]

Let \(\widetilde{\varphi}(h_1,h_2)\) be such that \(\widetilde{\varphi}(z_1,z_2;1,\xi)\) is infinitely differentiable in all its (six) real arguments and

\[ \widetilde{\varphi}(z_1,z_2;1,\xi)\equiv 0 \]

whenever at least one of the inequalities

\[ |z_1|>N,\qquad |z_2|>N,\qquad |\xi|>N,\qquad |\xi|<\varepsilon, \]

is satisfied, where \(N,\varepsilon\) are some positive numbers.

A function \(\varphi(h_1,h_2)\) representable as a sum with a finite number of terms

\[ \varphi(h_1,h_2) = \varphi_1(h_1\circ g_1',h_2\circ g_2') + \varphi_2(h_1\circ g_1'',h_2\circ g_2'') +\cdots, \]

where \(\varphi_1(h_1,h_2),\varphi_2(h_1,h_2),\ldots\) are functions of precisely the type just described, will be called finite.

Starting from a finite \(\varphi(h_1,h_2)\), construct a function \(f(g)\) on \(G\) by the formula

\[ f(g)=|\xi|^4\int \varphi\left(z,\frac{zg_1+g_3}{zg_2+g_4};\xi,\xi(zg_2+g_4)\right)\,dz, \tag{2} \]

where \(dz=dx\,dy,\ z=x+iy\), and the integral is taken over the whole plane of the complex variable \(z\) (in view of (1) it does not depend on \(\xi\)).

Introducing the notation \(dh=|\xi|^4dz\), formula (2) can be rewritten in the form

\[ f(g)=\int\varphi(h,h\circ g)\,dh. \tag{3} \]

The integral (3) is a relative invariant, namely,

\[ \int \varphi(h\circ \widetilde{g},h\circ \widetilde{g}g)\,dh = |\det \widetilde{g}|^{-2} \int \varphi(h,h\circ g)\,dh. \]

The function \(f(g)\), obtained by means of (2), (3), is harmonic.

Define the norm of \(\varphi(h_1,h_2)\) by the formula

\[ \|\varphi\|^2 = \int |\delta|^2 \left|\varphi(h_1,\hat{\delta}h_2)\right|^2 \,dh_1\,dh_2\,d\delta \qquad (d\delta=d\delta_1\,d\delta_2,\ \delta=\delta_1+i\delta_2). \tag{4} \]

The integral (4) does not depend on \(\xi_1,\xi_2\) and is a relative invariant, namely:

\[ \int |\delta|^2 \left|\varphi(h_1\circ g_1,\hat{\delta}h_2\circ g_2)\right|^2 \,dh_1\,dh_2\,d\delta = \]

\[ = |\det g_1|^{-2}|\det g_2|^{-2} \int |\delta|^2 \left|\varphi(h_1,\hat{\delta}h_2)\right|^2 \,dh_1\,dh_2\,d\delta. \]

Denote by \(\Phi\) the Hilbert space of functions \(\varphi(h_1,h_2)\) with finite norm (4).

The set \(\widetilde{\Phi}\) of finite \(\varphi(h_1,h_2)\) is contained in \(\Phi\) and is everywhere dense in it with respect to the norm (4).

Let \(\Gamma_0\) be the linear space of infinitely differentiable harmonic functions \(f(g)\) on \(G\) (it is not assumed that they are obtained from \(\varphi\)) satisfying the condition:

\[ \left| \frac{\partial^{k_1+k_2}}{\partial\gamma^{k_1}\partial\overline{\gamma}^{k_2}} \frac{\partial^{p_1+p_2+q_1+q_2}} {\partial\alpha^{p_1}\partial\overline{\alpha}^{p_2} \partial\beta^{q_1}\partial\overline{\beta}^{q_2}} f(\hat{a}\sigma\hat{b}) \right| < \frac{C(a,b)} {\left(1+|\alpha|^2+|\beta|^2+|\gamma|^2+|\alpha\beta|^2\right)^{\frac{k_1+k_2+1}{2}+\varepsilon}} \]

for any fixed \(\hat{a},\hat{b}\) and \(k_1+k_2+p_1+p_2+q_1+q_2\leqslant 2\). Here

\[ \sigma= \begin{pmatrix} \alpha&0\\ \gamma&\beta \end{pmatrix}, \qquad \hat{a}= \begin{pmatrix} 1&a\\ 0&1 \end{pmatrix}, \qquad \hat{b}= \begin{pmatrix} 1&b\\ 0&1 \end{pmatrix}, \]

\[ \frac{\partial}{\partial\alpha} = \frac{\partial}{\partial \operatorname{Re}\alpha} +i\frac{\partial}{\partial \operatorname{Im}\alpha}, \qquad \frac{\partial}{\partial\beta} = \frac{\partial}{\partial \operatorname{Re}\beta} +i\frac{\partial}{\partial \operatorname{Im}\beta}, \qquad \frac{\partial}{\partial\gamma} = \frac{\partial}{\partial \operatorname{Re}\gamma} +i\frac{\partial}{\partial \operatorname{Im}\gamma}. \]

I. For \(f(g)\in \Gamma_0\) the integral

\[ \|f\|^2=\frac{|\det g_1|^2|\det g_2|^2}{4\pi^2} \int\left\{\left|\frac{\partial}{\partial u}f(g_1\sigma g_2)\right|^2+ \left|\frac{\partial}{\partial v}f(g_1\sigma g_2)\right|^2\right\}\,d\sigma \tag{5} \]

\[ (\gamma=u+iv,\qquad d\sigma=d\alpha\,d\beta\,d\gamma) \]

is finite and does not depend on \(g_1,g_2\).

II. The linear space \(\Gamma_0\) with norm (5) is mapped isomorphically and isometrically onto a certain everywhere dense in \(\Phi\) linear space \(\Phi_0\), which includes the linear space \(\widetilde{\Phi}\) of finite \(\varphi(h_1,h_2)\), by means of the mutually inverse formulas:

\[ f(g)=\int \varphi(h,h\circ g)\,dh, \tag{6} \]

\[ \varphi(h_1,h_2)=\frac{1}{4\pi^2}\int \left[L_{z_0}f\left(h_1^{-1}\hat{\zeta}\hat{z}_0h_2\right)\right]_{z_0=0}\,d\zeta, \tag{7} \]

where

\[ \hat{\zeta}=\left\|\begin{matrix}\zeta&0\\0&1\end{matrix}\right\|, \qquad \hat{z}_0=\left\|\begin{matrix}1&0\\z_0&1\end{matrix}\right\|, \qquad L_{z_0}=\frac{\partial^2}{\partial x_0^2}+\frac{\partial^2}{\partial y_0^2}, \]

\[ z_0=x_0+iy_0,\qquad d\zeta=dt\,dw,\qquad \zeta=t+iw. \]

Moreover, as was stated, \(\|f\|^2=\|\varphi\|^2\). The integral

\[ \varphi(h_1,h_2)=\frac{1}{4\pi^2}|\det g_1|^2 \int\left[L_{z_0}f\left(g_1(h_1\circ g_1)^{-1}\hat{\zeta}\hat{z}_0(h_2\circ g_2^{-1})g_2\right)\right]_{z_0=0}\,d\zeta \tag{8} \]

does not depend on \(g_1,g_2\), so that (8) generalizes formula (7).

III. In view of what was said in the preceding paragraph, and as formulas (7), (6) show, the function \(f(g)\in\Gamma_0\) is completely determined by its values on the triangular group \(\Sigma\) of matrices

\[ \sigma=\left\|\begin{matrix}\alpha&0\\ \gamma&\beta\end{matrix}\right\| \]

(the argument of \(f\) in (7) is triangular).

It is also completely determined by its values on any surface \(g_1\Sigma g_2\) (see (8), (6)), obtained by a two-sided shift of the group \(\Sigma\).

For every infinitely smooth function \(f_0(\sigma)\) on \(\Sigma\), satisfying the condition

\[ \left| \frac{\partial^{k_1+k_2}}{\partial\gamma^{k_1}\partial\overline{\gamma}^{k_2}} \frac{\partial^{p_1+p_2+q_1+q_2}}{\partial\alpha^{p_1}\partial\overline{\alpha}^{p_2}\partial\beta^{q_1}\partial\overline{\beta}^{q_2}} \right| < \frac{C}{\left(1+|\alpha|^2+|\beta|^2+|\gamma|^2+|\alpha\beta|^2\right)^{\frac{k_1+k_2+1}{2}+\varepsilon}}, \]

\[ k_1+k_2+p_1+p_2+q_1+q_2\leq 2 \]

there exists a harmonic \(f(g)\) such that

\[ f(\sigma)\equiv f_0(\sigma). \]

This function is given by the formula

\[ f(g)=-\frac{1}{4\pi^2}\int\left\{\int \left[L_{z_0}f_0\left(h^{-1}\hat{\zeta}\hat{z}_0h\circ g\right)\right]_{z_0=0}\,d\zeta\right\}\,dh. \]

The question of whether \(f(g)\) belongs to the space \(\Gamma_0\) remains open for the present.

Gorky State University
named after N. I. Lobachevsky

Received
7 V 1963

CITED LITERATURE

\(^{1}\) I. M. Gel'fand, M. I. Graev, Tr. Mosk. matem. obshch., 8, 321 (1959).
\(^{2}\) I. M. Gel'fand, M. A. Naimark, Tr. Matem. inst. im. V. A. Steklova AN SSSR, 36 (1950).

Submission history

A. N. BOGAEVSKII