MATHEMATICS
Unknown
Submitted 1964-01-01 | RussiaRxiv: ru-196401.45534 | Translated from Russian

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MATHEMATICS

A. A. GOLDBERG

ON THE POSSIBLE MAGNITUDE OF THE LOWER ORDER OF AN ENTIRE FUNCTION WITH A FINITE DEFICIENT VALUE

(Presented by Academician A. N. Kolmogorov, 15 VI 1964)

Let \(f(z)\) be an entire function of order \(\rho\) and lower order \(\lambda\). We shall use the standard notation of Nevanlinna theory \((^{1})\). It is known that if \(\rho<\infty\) and \(f(z)\) has a finite Picard value, then \(\lambda=\rho\) and \(\rho\) is an integer. If \(f(z)\) has a finite deficient value in the sense of Nevanlinna, then it may happen that \(\lambda<\rho\), and the problem arises: to determine what values the lower order can assume for entire functions of fixed finite order \(\rho\) possessing a finite deficient value. This problem was included in the list of problems compiled by the participants of the Colloquium on the classical theory of functions, held in 1961 at Cornell University \((^{2,3})\). Earlier Edrei and Fuchs \((^{4})\) had put forward the hypothesis that \(\lambda\) and \(\rho\) are related by the inequality \(\lambda\geq \rho/2\). This hypothesis is cited in \((^{2,3})\) as the probable solution of the problem. From a theorem of I. V. Ostrovskii \((^{5})\) it follows that for \(\lambda<1/2\) an entire function cannot have finite deficient values (for \(\lambda<1/2\) this already follows from a result of Kjellberg \((^{6})\)). In the paper \((^{7})\) we showed that there exists an entire function with defect \(\delta(0)>0\) and with arbitrary prescribed \(\lambda\) and \(\rho\) such that \(1\leq \lambda\leq \rho<\infty\). Thus the Edrei–Fuchs hypothesis was disproved, but the problem was not completely solved. Here we construct an example of an entire function with \(\delta(0)>0\) and arbitrary \(\lambda\) and \(\rho\) such that \(1/2<\lambda\leq \rho<\infty\). Together with the result of I. V. Ostrovskii mentioned above, this gives a complete answer to the question posed in \((^{2,3})\)*.

Let numbers \(\lambda\) and \(\rho\) be given such that \(1/2<\lambda\leq \rho<\infty\). Choose an integer odd number \(n>\rho\) and a number \(\alpha\) such that \(\alpha\leq\lambda\) and \(1/2<\alpha<1\). Let

\[ g(\zeta)=\prod_{k=1}^{\infty}(1-\zeta k^{-\beta}),\qquad \text{where } \beta=1/\alpha. \]

It is known \((^{8})\) that there exists \(s_{0}(\eta)\) such that for \(s>s_{0}\) and for all \(\theta\), \(0\leq\theta\leq 2\pi\),

\[ \ln |g(se^{i\theta})|< s^\alpha\{\eta+\pi\cos\alpha(\theta-\pi)\cosec \pi\alpha\}, \]

where \(0<2\eta<\pi|\cos\alpha\pi|\cosec \pi\alpha\). The function \(w=g(\zeta)\) maps the finite \(\zeta\)-plane onto a certain Riemann surface \(F_{1}\), which has the following structure \((^{9})\). Let \(\xi_{k}\) be the sequence of zeros of \(g'(\zeta)\), \(k^\beta<\xi_{k}<(k+1)^\beta\), \(k=1,2,\ldots\), \(a_{k}=g(\xi_{k})\), \(\operatorname{sgn} a_{k}=(-1)^k\). Denote by \(B_{0}\) the copy of the \(w\)-plane with a cut along \((-\infty,a_{1})\), and by \(B_{j}\) the copy of the \(w\)-plane from which the points of the real axis have been removed except for the interval with endpoints at \(a_{j}\) and \(a_{j+1}\), \(j=1,2,\ldots\). By gluing the sheets \(B_{j-1}\) and \(B_{j}\) along the cut from \(a_{j}\) to \((-1)^j\infty\), \(j=1,2,\ldots\), we obtain the surface \(F_{1}\). For \(|a_{k}|\) in \((^{9})\) the estimate

\[ |a_{k}|<(\pi k)^{-1},\qquad k=1,2,\ldots \]

is established**. Denote by \(K_{1}\) the simply connected piece of the Riemann surface, \(K_{1}\subset F_{1}\), which consists of the intersections

\[ B_{k}\cap\{|w|<2\},\qquad k=0,\ldots,n-2, \]

and

\[ B_{n-1}\cap\{|w|<2,\ \operatorname{Re}w>0\}. \]

The boundary of \(K_{1}\) consists

* We note that it is not known to us whether there exists an entire function with a finite deficient value and with \(\lambda<\rho=\infty\).

** Using a result of Wiman \((^{10})\), it is easy to establish that

\[ |a_{k}|\sim (2\pi)^{-\beta/2}k^{-1/2}\times \exp(\pi k^\alpha \operatorname{ctg}\pi\alpha) \]

as \(k\to\infty\).

from the spiral $\sigma$ over $|w|=2$ and the segment $l=(-2i,2i)$. Let $F_0=F_1-K_1$. Denote by $K_2$ the part of the Riemann surface of the function $(w-1)^{1/n}$ lying over $|w|<2$, where on one of the sheets the semicircle $\{|w|<2,\ \operatorname{Re} w\leq 0\}$ is absent. The boundary of $K_2$ also consists of the spiral $\sigma$ and the segment $l$. Gluing the surfaces $F_0$ and $K_2$ along $\sigma$ and $l$, we obtain a simply connected Riemann surface $F_2$, which, evidently, is of parabolic type. The surface $F_2$ has an algebraic branch point of order $n-1$ over $w=1$ and simple branch points over the points $w=a_n,a_{n+1},\ldots$. Let $L$ be an infinite polygonal line on $F_2$ with consecutive vertices at the indicated branch points. Make a cut along $L$, and also along the ray $\{\operatorname{Im} w=0,\ \operatorname{Re} w>1\}$ on that sheet of the surface $F_2$ whose intersection with $F_0$ coincides with $B_0\cap F_0$. Then $F_2$ splits into two symmetric parts. Let $h(z)$ be an entire function mapping the finite $z$-plane $(z=x+iy=re^{i\varphi})$ onto $F_2$, with the positive real half-axis passing into $L$, $h(0)=1$. We indicate some properties of $h(z)$. The function $h(z)$ is real entire: for $x>0$ we have $|h(x)|<1$, since $h(x)\in L$;

\[ h(z)=1+c_n z^n+c_{n+1}z^{n+1}+\cdots, \tag{1} \]

where $c_n<0$ (the latter follows from the fact that $h(x)$ is a decreasing function in a sufficiently small neighborhood of $x=0$). It is easy to find the asymptotics of $h(z)$. Denote by $G_1$ and $G_2$ the images of $F_0$ under the mappings respectively by the functions $\zeta=g^{-1}(w)$ and $z=h^{-1}(w)$. Evidently, $G_1$ and $G_2$ are doubly connected domains with an infinitely distant point as one of the boundary components, symmetric with respect to the real axis; moreover, $\zeta=\zeta(z)=g^{-1}[h(z)]$ effects a conformal one-sheeted mapping of $G_2$ onto $G_1$, and in a neighborhood of $z=\infty$ we have an expansion of the form $\zeta(z)=dz+d_0+\cdots$, where $d>0$. Without loss of generality, the function $h(z)$ may be considered normalized so that $d=1$. Since $h(z)=g[\zeta(z)]$, for all $r>R_0>s_0$ and all $\varphi$, $0\leq \varphi\leq 2\pi$, the inequality

\[ \ln |h(re^{i\varphi})|<r^\alpha\{2\eta+\pi\cos\alpha(\varphi-\pi)\operatorname{cosec}\pi\alpha\} \tag{2} \]

holds.

We shall denote by $C$ with subscripts positive constants which may depend only on $\alpha$ and $n$. Taking (1) and (2) into account, it is easy to see that $\ln M(r,h)<C_1\Psi(r)$, $0<r<\infty$, where $\Psi(r)=r^{n+\alpha}(r^\alpha+r^n)^{-1}$. Using (1), we find that there exist such $R_1$, $0<R_1<R_0$, and $\varphi_1$, $0<\varphi_1<\pi/2n$, that for all $r\in[0,R_1]$ and $|\varphi|\leq \varphi_1$,

\[ \ln |h(re^{i\varphi})|\leq -C_2 r^n . \]

From (2) there follows the existence of such $R_2>R_0$ and $\varphi_2$, $0<\varphi_2<\pi(1-\beta/2)$, that for all $r>R_2$ and $|\varphi|\leq \varphi_2$ one has

\[ \ln |h(re^{i\varphi})|\leq -C_3 r^\alpha . \]

When $x\in[R_1,R_2]$, we have $\ln |h(x)|<0$, and, by virtue of the uniform continuity of $|h(re^{i\varphi})|$, $r\leq R_2$, there exists such $\varphi_3$, $0<\varphi_3<\pi$, that for all $r\in[R_1,R_2]$ and $|\varphi|\leq \varphi_3$ the estimate

\[ \ln |h(re^{i\varphi})|\leq -C_4 \]

holds. Combining these estimates, we obtain that for all $r$, $0\leq r<\infty$, and $|\varphi|\leq \varphi_0=\min(\varphi_1,\varphi_2,\varphi_3)$ the inequality $\ln |h(re^{i\varphi})|\leq -C_5\Psi(r)$ is valid.

Let $\{r_k\}$ be a nondecreasing sequence of positive numbers tending to $+\infty$ such that $\sum r_k^{-n}<\infty$. Denote by $\nu(r)$ the number of points $r_k$ on the segment $[0,r]$. By virtue of (1), the infinite product

\[ f(z)=\prod_{k=1}^{\infty} h(z/r_k) \]

converges absolutely and represents an entire function. Taking into account the estimates for $h(z)$, we obtain that

\[ \ln M(r,f)\leq C_1\sum_{k=1}^{\infty}\Psi(r/r_k)=C_1\Phi(r) \tag{3} \]

and for all \(|\varphi|\leqslant \varphi_0\) one has \(\ln |f(re^{i\varphi})|\leqslant -C_5\Phi(r)\), whence it follows that

\[ m(r,0,f)\geqslant C_6\Phi(r),\qquad C_6=\frac{\psi_0}{\pi}C_5 . \tag{4} \]

Comparing (3) and (4), we find

\[ \delta(0,f)\geqslant \liminf_{r\to\infty} m(r,0,f)/\ln M(r,f)\geqslant C_7>0, \]

where \(C_7=C_6C_1^{-1}\). Thus, for any choice of the sequence \(r_k\), the entire function \(f(z)\) has at zero a defect not less than a certain positive number \(C_7\).

We shall now show that the sequence \(r_k\) can be chosen so that the function \(f(z)\) has prescribed in advance \(\rho\) and \(\lambda\), \(\alpha\leqslant \lambda\leqslant \rho<n\). Observe that, in view of (3) and (4), we have \(C_6\leqslant \ln M(r,f)/\Phi(r)\leqslant C_1\), and therefore the order and the lower order of \(\ln M(r,f)\) and \(\Phi(r)\) coincide. Writing \(\Phi(r)\) in the form of a Stieltjes integral, integrating by parts and noting that \(v(r)=0\) for \(0\leqslant r<r_1\) and \(v(r)=o(r^n)\) as \(r\to\infty\), we obtain

\[ \Phi(r)=\int_0^\infty v(t)\Psi'\!\left(\frac{r}{t}\right)r\frac{dt}{t^2} =\int_0^\infty v(r\tau)\Psi'\!\left(\frac{1}{\tau}\right)\frac{d\tau}{\tau^2}. \]

It is easy to verify that

\[ C_8<\Psi'(1/\tau)\tau^{\alpha-1}(1+\tau^{n-\alpha})<C_9, \]

and therefore

\[ C_9^{-1}\Phi(r)<\int_0^\infty \frac{v(r\tau)}{\tau^{1+\alpha}}\frac{d\tau}{1+\tau^{n-\alpha}}<C_8^{-1}\Phi(r). \]

It is now clear that it suffices to choose the function \(v(r)\) so that: 1) for all \(r\) the inequalities \(r^\lambda-1\leqslant v(r)\leqslant r^\rho+1\) hold; 2) on some sequence of intervals \((\gamma_k,\exp\exp \gamma_k)\), \(\gamma_k\to\infty\), one has \(v(r)\leqslant r^\lambda+1\); 3) on a sequence of intervals \((\omega_k,\exp\exp \omega_k)\), \(\omega_k\to\infty\), \(v(r)\geqslant r^\rho-1\) holds. Then the function \(\Phi(r)\), and with it also \(f(z)\), will have order \(\rho\) and lower order \(\lambda\).

Remark. If one requires only that \(1\leqslant \lambda\leqslant \rho<\infty\), then, using the same idea, the desired example can be constructed much more simply.

For the function \(h(z)\) we take

\[ h(z)=e^{-z}\sum_{k=0}^{n-1} z^k/(k!),\qquad \alpha=1. \]

Then the preceding arguments can be repeated, but the investigation of the properties of \(h(z)\) is simplified, since

\[ h'(z)=-e^{-z}z^{\,n-1}/(n-1)! . \]

Lviv State University
named after I. Franko

Received
8 VI 1964

REFERENCES

  1. R. Nevanlinna, Univalent analytic functions, Moscow–Leningrad, 1941.
  2. Bull. Am. Math. Soc., 68, No. 1, 21 (1962).
  3. Collection “Trans. Math. Inst.”, 7, No. 5, 133 (1963).
  4. A. Edrei, W. H. J. Fuchs, Trans. Am. Math. Soc., 93, 292 (1959).
  5. I. V. Ostrovskii, DAN, 150, 32 (1963).
  6. B. Kjellberg, Math. Scand., 8, 189 (1960).
  7. A. A. Gol’dberg, Siberian Mathematical Journal, 5, 54 (1964).
  8. B. Ya. Levin, Distribution of zeros of entire functions, Moscow, 1956.
  9. H. Schubart, H. Wittich, Math. Ann., 124, 450 (1952).
  10. A. Wiman, Math. Ann., 76, 197 (1915).

Submission history

MATHEMATICS